What is the probability that a number formed | vedclass

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(A) The total number of $5$-digit numbers formed using the digits $1, 2, 3, 4, 5$ is $5! = 120$.$A$ number is divisible by $4$ if the number formed by

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$1/5$

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(A) The total number of $5$-digit numbers formed using the digits $1, 2, 3, 4, 5$ is $5! = 120$.$A$ number is divisible by $4$ if the number formed by its last two digits is divisible by $4$.The possible pairs from the given digits that are divisible by $4$ are $12, 24, 32, 52$.For each of these $4$ pairs,the remaining $3$ digits can be arranged in $3! = 6$ ways.Total favorable outcomes $= 4 	imes 6 = 24$.Probability $= \frac{24}{120} = \frac{1}{5}$.

What is the probability that a number formed using all the digits $1, 2, 3, 4, 5$ is divisible by $4$?

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