What is the mean deviation of the numbers 1, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given set of numbers is $1, 2, 3, 4, 5$.First,calculate the mean $(\overline{x})$:$\overline{x} = \frac{1 + 2 + 3 + 4 + 5}{5} = \frac{15}{5} =

Vedclass · Accepted Answer

$1.2$

Vedclass · Answer

(B) The given set of numbers is $1, 2, 3, 4, 5$.First,calculate the mean $(\overline{x})$:$\overline{x} = \frac{1 + 2 + 3 + 4 + 5}{5} = \frac{15}{5} = 3$.Next,calculate the mean deviation about the mean using the formula $\frac{\sum |x_i - \overline{x}|}{N}$:$|1 - 3| = 2$$|2 - 3| = 1$$|3 - 3| = 0$$|4 - 3| = 1$$|5 - 3| = 2$Sum of absolute deviations $= 2 + 1 + 0 + 1 + 2 = 6$.Mean deviation $= \frac{6}{5} = 1.2$.

Size $(x)$	$1$	$3$	$5$	$7$	$9$	$11$	$13$	$15$
Frequency $(f)$	$3$	$3$	$4$	$14$	$7$	$4$	$3$	$4$

What is the mean deviation of the numbers $1, 2, 3, 4, 5$?

Similar Questions

If $a_0, a_1, \ldots, a_{11}$ are in an arithmetic progression with common difference $d$,then their mean deviation from their arithmetic mean is

Let $S$ be the set of all values of $a_1$ for which the mean deviation about the mean of $100$ consecutive positive integers $a_1, a_2, a_3, \ldots, a_{100}$ is $25$. Then $S$ is

The mean deviation from the mean for the observations $1, 3, 5, 7, 11, 13, 17, 19, 23$ is

The mean deviation about the mean of the following data is nearly:
Size $(x)$ $1$ $3$ $5$ $7$ $9$ $11$ $13$ $15$
Frequency $(f)$ $3$ $3$ $4$ $14$ $7$ $4$ $3$ $4$

The mean deviation about the median of the numbers $2, 3, 5, 20, 17, 15, 13, 11, 9, 7$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module