The volume of a sphere is 1.76 cm^3. The vol | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given,the volume of one sphere $V_1 = 1.76 \ cm^3$.Number of spheres $n = 25$.The total volume $V = n 	imes V_1 = 25 	imes 1.76 \ cm^3 = 44.0 \

Vedclass · Accepted Answer

$44.0$

Vedclass · Answer

(B) Given,the volume of one sphere $V_1 = 1.76 \ cm^3$.Number of spheres $n = 25$.The total volume $V = n 	imes V_1 = 25 	imes 1.76 \ cm^3 = 44.0 \ cm^3$.According to the rules of significant figures,when multiplying,the result should have the same number of significant figures as the measurement with the least number of significant figures.Here,$1.76$ has $3$ significant figures and $25$ is an exact number (infinite significant figures).Therefore,the result should be reported to $3$ significant figures.Thus,$44.0 \ cm^3$ is the correct answer.

$A$. $74.083$	$I$. $3$
$B$. $0.029$	$II$. $4$
$C$. $0.002407$	$III$. $2$
$D$. $2.74 \times 10^7$	$IV$. $5$

Column-$I$	Column-$II$
$(a)$ $0.007\ m^2$	$(p)$ $2$
$(b)$ $2.64 \times 10^{24}\ kg$	$(q)$ $1$
$(c)$ $0.0021\ g\ cm^{-3}$	$(r)$ $4$
$(d)$ $0.0006032\ J$	$(s)$ $3$

The volume of a sphere is $1.76 \ cm^3$. The volume of $25$ such spheres in terms of significant figures is ...... $cm^3$.

Similar Questions

If the length of a rod is measured as $830600 \ mm$, then the number of significant figures in the measurement is

The number of significant figures in the simplification of $\frac{0.501}{0.05}(0.312-0.03)$ is

Match the measurements given in List-$I$ with the number of significant figures given in List-$II$.
$A$. $74.083$ $I$. $3$
$B$. $0.029$ $II$. $4$
$C$. $0.002407$ $III$. $2$
$D$. $2.74 \times 10^7$ $IV$. $5$

The correct answer is:

Match the number of significant figures in the given column:

Column-$I$ Column-$II$

$(a)$ $0.007\ m^2$ $(p)$ $2$

$(b)$ $2.64 \times 10^{24}\ kg$ $(q)$ $1$

$(c)$ $0.0021\ g\ cm^{-3}$ $(r)$ $4$

$(d)$ $0.0006032\ J$ $(s)$ $3$

The area of a rectangular field (in $m^{2}$) of length $55.3 \ m$ and breadth $25 \ m$ after rounding off the value for correct significant digits is

Vedclass Test Series

Exam Paper Generator

Online Exam Module