(A) The condition for constructive interference (diffraction) from a crystal lattice is given by Bragg's Law: $2d \sin \theta = n\lambda$.Here,the int

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(A) The condition for constructive interference (diffraction) from a crystal lattice is given by Bragg's Law: $2d \sin \theta = n\lambda$.Here,the interplanar spacing is given as $d = b$.For direct reflection (backscattering),the angle of incidence $\theta$ with respect to the atomic planes is $90^\circ$.Substituting $\theta = 90^\circ$ into Bragg's Law: $2b \sin(90^\circ) = n\lambda$.Since $\sin(90^\circ) = 1$,we get $2b = n\lambda$.Therefore,the wavelength is $\lambda = \frac{2b}{n}$.

Class 12 Physics Dual Nature of Radiation and matter Matter Waves and de Broglie Wavelength

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An electron beam is incident on a crystal. The interplanar spacing of the crystal is $b$. Which of the following de Broglie wavelengths of the electron beam will result in direct reflection?

A
$\lambda = \frac{2b}{n}$
B
$\lambda = \frac{b}{n}$
C
$\lambda = \frac{3b}{n}$
D
$\lambda = \frac{4b}{n}$

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Dual Nature of Radiation and matter

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Matter Waves and de Broglie Wavelength

We wish to see inside an atom. Assuming the atom to have a diameter of $100 \ pm$, this means that one must be able to resolve a width of say $10 \ pm$. If an electron microscope is used, the minimum electron energy required is about....... $KeV$.

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If the velocity of a moving particle is reduced to half, what will be the percentage change in its de Broglie wavelength?

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The de-Broglie wavelength of a body of mass $1 \ kg$ moving with a velocity of $2000 \ m/s$ is:

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An electron beam is incident on a crystal. The interplanar spacing of the crystal is $b$. Which of the following de Broglie wavelengths of the electron beam will result in direct reflection?

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We wish to see inside an atom. Assuming the atom to have a diameter of $100 \ pm$, this means that one must be able to resolve a width of say $10 \ pm$. If an electron microscope is used, the minimum electron energy required is about....... $KeV$.

If the de Broglie wavelengths associated with a proton and an $\alpha$-particle are equal,then the ratio of velocities of the proton and the $\alpha$-particle will be

The de-Broglie wavelength of a moving bus with speed $v$ is $\lambda$. Some passengers left the bus at a stoppage. Now, when the bus moves with twice its initial speed, its kinetic energy is found to be twice its initial value. What is the de-Broglie wavelength of the bus now?

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