What is the ratio of the de Broglie wavelengt | vedclass

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(A) The de Broglie wavelength $\lambda$ is given by the formula $\lambda = \frac{h}{p} = \frac{h}{mv}$,where $h$ is Planck's constant,$m$ is the mass,

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(A) The de Broglie wavelength $\lambda$ is given by the formula $\lambda = \frac{h}{p} = \frac{h}{mv}$,where $h$ is Planck's constant,$m$ is the mass,and $v$ is the velocity.Since both the proton and the neutron are moving with the same velocity $v$,the ratio of their wavelengths is $\frac{\lambda_P}{\lambda_N} = \frac{h / (m_P v)}{h / (m_N v)} = \frac{m_N}{m_P}$.The mass of a neutron $(m_N \approx 1.6749 	imes 10^{-27} 	ext{ kg})$ is slightly greater than the mass of a proton $(m_P \approx 1.6726 	imes 10^{-27} 	ext{ kg})$.Therefore,the ratio $\frac{m_N}{m_P} \approx 1.001$,which is approximately $1$.

What is the ratio of the de Broglie wavelengths of a proton and a neutron moving with the same velocity?

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