For a given source,with an increase in intensity of incident radiation,the . . . . . .

Light of a certain frequency and intensity incident on a photosensitive material causes the photoelectric effect. If both the frequency and intensity are doubled,the photoelectric saturation current becomes

$A$ photoelectric cell is illuminated by a point source of light $1 \ m$ away. When the source is shifted to $2 \ m$,then:

The curve between the work function of a metal $(\phi_o)$ and its temperature $(T)$ will be:

In a photoelectric experiment,keeping the frequency of incident radiation and the accelerating potential fixed,if the intensity of incident light is increased,then:

In a photoelectric experiment,a parallel beam of monochromatic light with power of $200 \ W$ is incident on a perfectly absorbing cathode of work function $6.25 \ eV$. The frequency of light is just above the threshold frequency so that the photoelectrons are emitted with negligible kinetic energy. Assume that the photoelectron emission efficiency is $100 \%$. $A$ potential difference of $500 \ V$ is applied between the cathode and the anode. All the emitted electrons are incident normally on the anode and are absorbed. The anode experiences a force $F = n \times 10^{-4} \ N$ due to the impact of the electrons. The value of $n$ is. . . . .
Mass of the electron $m_e = 9 \times 10^{-31} \ kg$ and $1.0 \ eV = 1.6 \times 10^{-19} \ J$.