The de Broglie wavelengths of an electron $(e)$,proton $(p)$,neutron $(n)$,and $\alpha$-particle are $\lambda_e, \lambda_p, \lambda_n$,and $\lambda_\alpha$ respectively. All have the same kinetic energy of $1 \ MeV$. Which of the following represents the correct increasing order of their wavelengths?

• A
  $\lambda_e < \lambda_p < \lambda_n < \lambda_\alpha$
• B
  $\lambda_\alpha < \lambda_n < \lambda_p < \lambda_e$
• C
  $\lambda_e > \lambda_p > \lambda_n > \lambda_\alpha$
• D
  $\lambda_p < \lambda_e < \lambda_\alpha < \lambda_n$