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(A) The photoelectric effect occurs when the frequency of incident radiation $v$ is greater than the threshold frequency $v_0$ of the metal. Ultraviol

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Infrared rays

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(A) The photoelectric effect occurs when the frequency of incident radiation $v$ is greater than the threshold frequency $v_0$ of the metal. Ultraviolet $(UV)$ rays have a higher frequency than visible light and infrared rays. Infrared rays have a lower frequency than $UV$ rays,meaning $v_{IR} Since the photoelectric effect is triggered by $UV$ rays,the threshold frequency $v_0$ must be less than or equal to $v_{UV}$. Because $v_{IR} $X$-rays and $\gamma$-rays have frequencies much higher than $UV$ rays,so they will definitely cause the photoelectric effect.

Photoelectric effect occurs when ultraviolet rays are incident on a metal plate. It does not occur when which of the following are incident?

Similar Questions

The figure shows the variation of photocurrent with anode potential for four different radiations. Let $I_a, I_b, I_c$ and $I_d$ be the intensities for the curves $a, b, c$ and $d$ respectively $[f_a, f_b, f_c$ and $f_d$ are frequencies respectively].

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