If a TV transmission antenna covers a radius | vedclass

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(B) The range $d$ of a $TV$ transmission antenna of height $h$ is given by the formula $d = \sqrt{2 R_e h}$,where $R_e$ is the radius of the Earth.Squ

Vedclass · Accepted Answer

$1280$

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(B) The range $d$ of a $TV$ transmission antenna of height $h$ is given by the formula $d = \sqrt{2 R_e h}$,where $R_e$ is the radius of the Earth.Squaring both sides,we get $d^2 = 2 R_e h$.Therefore,the height $h = \frac{d^2}{2 R_e}$.Given $d = 128 \, km = 128 	imes 10^3 \, m$ and $R_e \approx 6.4 	imes 10^6 \, m$.Substituting the values: $h = \frac{(128 	imes 10^3)^2}{2 	imes 6.4 	imes 10^6} = \frac{16384 	imes 10^6}{12.8 	imes 10^6} = \frac{16384}{12.8} = 1280 \, m$.

List-$I$ (Signal)	List-$II$ (Bandwidth)
$i$. Speech Signal	$a$. $4.2 \text{ MHz}$
$ii$. Music Signal	$b$. $6 \text{ MHz}$
$iii$. Video Signal	$c$. $20 \text{ kHz}$
$iv$. $T$.$V$. Signal	$d$. $2.8 \text{ kHz}$

If a $TV$ transmission antenna covers a radius of $128 \, km$,what should be the height of the antenna in $m$?

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Match the following:
List-$I$ (Signal) List-$II$ (Bandwidth)
$i$. Speech Signal $a$. $4.2 \text{ MHz}$
$ii$. Music Signal $b$. $6 \text{ MHz}$
$iii$. Video Signal $c$. $20 \text{ kHz}$
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