An open vessel at 27,^oC is heated such that | vedclass

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(A) Since the vessel is open,the pressure remains constant $(P = 	ext{constant})$. According to Charles's Law for a constant pressure and volume,the

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$750$

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(A) Since the vessel is open,the pressure remains constant $(P = 	ext{constant})$. According to Charles's Law for a constant pressure and volume,the number of moles $n$ is inversely proportional to temperature $T$ $(n_1T_1 = n_2T_2)$. Let the initial number of moles be $n_1 = n$ and initial temperature $T_1 = 27 + 273 = 300\,K$. After heating,$\frac{3}{5}$ of the air is expelled,so the remaining moles $n_2 = n - \frac{3}{5}n = \frac{2}{5}n$. Using the relation $n_1T_1 = n_2T_2$: $n 	imes 300 = \frac{2}{5}n 	imes T_2$. $T_2 = \frac{300 	imes 5}{2} = 750\,K$.

An open vessel at $27\,^oC$ is heated such that $\frac{3}{5}$ of the air in it is expelled. Assuming the volume of the vessel remains constant,calculate the temperature in $K$ to which the vessel was heated.

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