The rms speed of N_2 molecules in a gas is u. | vedclass

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(B) The $rms$ speed is given by the formula $u = \sqrt{\frac{3RT}{M}}$.Initially,for $N_2$ molecules,$u = \sqrt{\frac{3RT}{M}}$,where $M$ is the molar

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$2u$

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(B) The $rms$ speed is given by the formula $u = \sqrt{\frac{3RT}{M}}$.Initially,for $N_2$ molecules,$u = \sqrt{\frac{3RT}{M}}$,where $M$ is the molar mass of $N_2$.When the temperature is doubled $(T' = 2T)$ and $N_2$ dissociates into $N$ atoms,the new molar mass becomes $M' = M/2$.The new $rms$ speed $u'$ is given by $u' = \sqrt{\frac{3R(2T)}{M/2}} = \sqrt{\frac{3R(4T)}{M}} = 2 \sqrt{\frac{3RT}{M}} = 2u$.

The $rms$ speed of $N_2$ molecules in a gas is $u$. If the temperature is doubled and the nitrogen molecules dissociate into nitrogen atoms,what will be the new $rms$ speed?

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