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(A) The decomposition of hydrogen peroxide is given by the equation: $2H_2O_2(aq) \rightarrow 2H_2O(l) + O_2(g)$.$1$ volume of $H_2O_2$ solution gives

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(A) The decomposition of hydrogen peroxide is given by the equation: $2H_2O_2(aq) ightarrow 2H_2O(l) + O_2(g)$.$1$ volume of $H_2O_2$ solution gives $10$ volumes of $O_2$ at $STP$.$2 	imes 34 \ g$ of $H_2O_2$ produces $22400 \ mL$ of $O_2$ at $STP$.So,$22400 \ mL$ of $O_2$ is produced by $68 \ g$ of $H_2O_2$.Therefore,$1000 \ mL$ of $O_2$ (for $10$ volume) is produced by $(68 	imes 1000) / 22400 \approx 3.036 \ g$ of $H_2O_2$.Since $1000 \ mL$ of $H_2O_2$ solution weighs approximately $1000 \ g$,the percentage concentration is $(3.036 / 1000) 	imes 100 \approx 3\%$.

$A$ commercial sample of hydrogen peroxide is labeled as $10$ volume. What is its percentage concentration approximately (in $\%$)?

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