At $25^o C$,the molar conductivity of a $0.1 \, N \, CH_3COOH$ solution is $80 \, S \, cm^2 \, mol^{-1}$ and the molar conductivity at infinite dilution is $400 \, S \, cm^2 \, mol^{-1}$. What is the degree of dissociation $(\alpha)$ of $CH_3COOH$?
- A$1$
- B$0.2$
- C$0.1$
- D$0.5$
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What will be the concentration of $NaCl$ solution,if the molar conductivity and conductivity of $NaCl$ solution are $124.3 \ \Omega^{-1} \ cm^{2} \ mol^{-1}$ and $1.243 \times 10^{-4} \ \Omega^{-1} \ cm^{-1}$ respectively?
The resistance of $0.05\, M$ solution of oxalic acid is $200\, \Omega$ and the cell constant is $2.0\, cm^{-1}$. The equivalent conductance in $S\, cm^2\, eq^{-1}$ will be:
Medium
View SolutionAssertion : On increasing dilution,the specific conductance keeps on increasing.
Reason : On increasing dilution,the degree of ionization of a weak electrolyte increases and the mobility of ions also increases.
Reason : On increasing dilution,the degree of ionization of a weak electrolyte increases and the mobility of ions also increases.
MediumAIIMS 2015
View SolutionIf the resistivity of a $0.8 \ M \ KCl$ solution is $2.5 \times 10^{-3} \ \Omega \ cm$,calculate the molar conductivity of the solution.
The molar conductivity of $KCl$ solutions at different concentrations at $298 \, K$ are given below:
$c^{1/2} / (mol \, L^{-1})^{1/2}$ $\Lambda_m / S \, cm^2 \, mol^{-1}$ $0.000198$ $148.61$ $0.000309$ $148.29$ $0.000521$ $147.81$ $0.000989$ $147.09$
Show that a plot between $\Lambda_m$ and $c^{1/2}$ is a straight line. Determine the values of $\Lambda_m^o$ and $A$ for $KCl$.
| $c^{1/2} / (mol \, L^{-1})^{1/2}$ | $\Lambda_m / S \, cm^2 \, mol^{-1}$ |
| $0.000198$ | $148.61$ |
| $0.000309$ | $148.29$ |
| $0.000521$ | $147.81$ |
| $0.000989$ | $147.09$ |
Show that a plot between $\Lambda_m$ and $c^{1/2}$ is a straight line. Determine the values of $\Lambda_m^o$ and $A$ for $KCl$.
Medium
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