Calculate the molar conductivity of $NH_4OH$ at infinite dilution,given that the molar conductivities of $Ba(OH)_2$,$BaCl_2$,and $NH_4Cl$ are $523.28$,$280.0$,and $129.8 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively.

$A$ solution of concentration $C \ g \ equiv/L$ has a specific resistance $R$. The equivalent conductance of the solution is

Calculate the molar conductivity of $CH_2ClCOOH$ at zero concentration if molar conductivities of $HCl$,$KCl$,and $CH_2ClCOOK$ at zero concentration are $4.2$,$1.4$,and $1.1 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively.

Given the limiting molar conductivities at $25^{\circ}C$ for the following electrolytes in $S \, cm^{2} \, mol^{-1}$:
$KCl = 149.9$
$KNO_{3} = 145.0$
$HCl = 426.2$
$NaOAc = 91.0$
$NaCl = 126.5$
Calculate $\Lambda^{\infty}_{HOAc}$ using the Kohlrausch law of independent migration of ions.

The specific conductance of a solution containing $1.0 \ g$ of anhydrous $BaCl_2$ in $200 \ cm^3$ of solution is $0.0058 \ S \ cm^{-1}$. Calculate the molar and equivalent conductivity of the solution. (Molar mass of $BaCl_2 = 208 \ g \ mol^{-1}$)

The resistance of $0.01 \ N$ $NaCl$ solution at $25 \ ^oC$ is $200 \ \Omega$. The cell constant of the conductivity cell is $1 \ cm^{-1}$. The equivalent conductance is: