What is 'A' in the following reaction?2Fe^{3+ | vedclass

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(B) In the given redox reaction: $2Fe^{3+} + Sn^{2+} 	o 2Fe^{2+} + A$$1$. Analyze the oxidation states:- $Fe^{3+}$ is reduced to $Fe^{2+}$ (gain of e

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$Sn^{4+}_{(aq)}$

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(B) In the given redox reaction: $2Fe^{3+} + Sn^{2+} 	o 2Fe^{2+} + A$$1$. Analyze the oxidation states:- $Fe^{3+}$ is reduced to $Fe^{2+}$ (gain of electrons).- $Sn^{2+}$ is oxidized to $Sn^{4+}$ (loss of electrons).$2$. Balance the charge:- Left side total charge: $2(+3) + (+2) = +8$.- Right side total charge: $2(+2) + x = +4 + x$.- For the reaction to be balanced,$+8 = +4 + x$,so $x = +4$.Therefore,'$A$' is $Sn^{4+}_{(aq)}$.

What is '$A$' in the following reaction?
$2Fe^{3+} + Sn^{2+} \to 2Fe^{2+} + A$

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What is '$A$' in the following reaction?$2Fe^{3+} + Sn^{2+} \to 2Fe^{2+} + A$