H_2O is polar while BeF_2 is not. The reason | vedclass

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(A) The polarity of a molecule is determined by its dipole moment $(\mu)$.$H_2O$ has a bent (angular) geometry due to the presence of two lone pairs o

Vedclass · Accepted Answer

$H_2O$ is angular while $BeF_2$ is linear.

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(A) The polarity of a molecule is determined by its dipole moment $(\mu)$.$H_2O$ has a bent (angular) geometry due to the presence of two lone pairs on the oxygen atom,which results in a net dipole moment $(\mu 
eq 0)$,making it polar.$BeF_2$ has a linear geometry ($F-Be-F$ bond angle is $180^{\circ}$),where the two bond dipoles are equal in magnitude and opposite in direction,canceling each other out,resulting in a net dipole moment of zero $(\mu = 0)$,making it non-polar.

$H_2O$ is polar while $BeF_2$ is not. The reason for this is ...

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