Which of the following is the correct decreas | vedclass

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(C) The correct decreasing order of bond angles is $NO_2^+ > NO_2 > NO_2^-$.$1$. $NO_2^+$ is a linear molecule with $sp$ hybridization and a bond angl

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$NO_2^+ > NO_2 > NO_2^-$

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(C) The correct decreasing order of bond angles is $NO_2^+ > NO_2 > NO_2^-$.$1$. $NO_2^+$ is a linear molecule with $sp$ hybridization and a bond angle of $180^{\circ}$. It has no lone pair on the central nitrogen atom.$2$. $NO_2$ has one unpaired electron on the nitrogen atom,which exerts less repulsion than a lone pair,resulting in a bond angle of approximately $134^{\circ}$.$3$. $NO_2^-$ has one lone pair on the nitrogen atom,which exerts strong repulsion on the bonding pairs,reducing the bond angle to approximately $115^{\circ}$.

List-$I$ (Molecule)	List-$II$ (Shape)
$A$. $BrF_5$	$I$. $T$-shape
$B$. $H_2O$	$II$. See-saw
$C$. $ClF_3$	$III$. Bent
$D$. $SF_4$	$IV$. Square pyramidal

Which of the following is the correct decreasing order of bond angles?

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Match List-$I$ with List-$II$:

List-$I$ (Molecule) List-$II$ (Shape)

$A$. $BrF_5$ $I$. $T$-shape

$B$. $H_2O$ $II$. See-saw

$C$. $ClF_3$ $III$. Bent

$D$. $SF_4$ $IV$. Square pyramidal

Which compound has the maximum number of lone pairs of electrons on the central atom?

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