Which compound has the maximum number of lone | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} (V - M - C + A)$,where $V$ is the n

Vedclass · Accepted Answer

$[I_3]^-$

Vedclass · Answer

(D) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} (V - M - C + A)$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.$A) [ClO_3]^-$: Central atom $Cl$ $(V=7)$. $O$ is divalent $(M=0)$. Anionic charge $A=1$. $	ext{Lone pairs} = \frac{1}{2} (7 - 0 - 0 + 1) = 4$ electrons,which corresponds to $1$ lone pair.$B) XeF_4$: Central atom $Xe$ $(V=8)$. $F$ is monovalent $(M=4)$. $	ext{Lone pairs} = \frac{1}{2} (8 - 4) = 2$ lone pairs.$C) SF_4$: Central atom $S$ $(V=6)$. $F$ is monovalent $(M=4)$. $	ext{Lone pairs} = \frac{1}{2} (6 - 4) = 1$ lone pair.$D) [I_3]^-$: Central atom $I$ $(V=7)$. Two $I$ atoms are attached $(M=2)$. Anionic charge $A=1$. $	ext{Lone pairs} = \frac{1}{2} (7 - 2 + 1) = 3$ lone pairs.Comparing the values,$[I_3]^-$ has the maximum number of lone pairs $(3)$.

Which compound has the maximum number of lone pairs of electrons on the central atom?

Similar Questions

The shape of $O_2F_2$ is similar to that of:

In the $NO_3^-$ ion,what are the number of bond pairs and lone pairs of electrons on the $N$ atom,respectively?

$A$ central atom in a molecule has two lone pairs of electrons and forms three single bonds. The shape of this molecule is

The correct order of bond angle is:

In the ozone $(O_3)$ molecule,the formal charge on the central oxygen atom is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module