Which of the following products is a Schiff b | vedclass

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(B) Schiff base is formed by the reaction of a primary amine with an aldehyde or ketone,resulting in the formation of an imine $(R-CH=N-R')$.$1$. $C_2

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$b$

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(B) Schiff base is formed by the reaction of a primary amine with an aldehyde or ketone,resulting in the formation of an imine $(R-CH=N-R')$.$1$. $C_2H_5NH_2 + HNO_2 \rightarrow C_2H_5OH + N_2 + H_2O$ (Alcohol is formed).$2$. $C_2H_5NH_2 + C_6H_5CHO \rightarrow C_6H_5CH=NC_2H_5 + H_2O$ (This is a Schiff base).$3$. $C_2H_5NH_2 + NOCl \rightarrow C_2H_5Cl + N_2 + H_2O$ (Alkyl chloride is formed).$4$. $C_2H_5NH_2 + C_6H_5SO_2Cl \rightarrow C_6H_5SO_2NHC_2H_5 + HCl$ ($N$-ethylbenzenesulfonamide is formed).Therefore,the product $b$ is a Schiff base.

Which of the following products is a Schiff base?
$C_2H_5NH_2 \xrightarrow{HNO_2} a$
$C_2H_5NH_2 \xrightarrow{C_6H_5CHO} b$
$C_2H_5NH_2 \xrightarrow{NOCl} c$
$C_2H_5NH_2 \xrightarrow{C_6H_5SO_2Cl} d$

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Which of the following products is a Schiff base?$C_2H_5NH_2 \xrightarrow{HNO_2} a$$C_2H_5NH_2 \xrightarrow{C_6H_5CHO} b$$C_2H_5NH_2 \xrightarrow{NOCl} c$$C_2H_5NH_2 \xrightarrow{C_6H_5SO_2Cl} d$