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(C) The alkaline hydrolysis of ethyl isocyanate $(C_2H_5 - N = C = O)$ yields ethylamine $(C_2H_5NH_2)$.$C_2H_5 - N = C = O + 2KOH \rightarrow C_2H_5N

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Isobutane

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(C) The alkaline hydrolysis of ethyl isocyanate $(C_2H_5 - N = C = O)$ yields ethylamine $(C_2H_5NH_2)$.$C_2H_5 - N = C = O + 2KOH \rightarrow C_2H_5NH_2 + K_2CO_3$.When ethylamine $(C_2H_5NH_2)$ reacts with $t$-butyl magnesium bromide $((CH_3)_3CMgBr)$,the Grignard reagent acts as a base and abstracts the acidic proton from the amine group.$C_2H_5NH_2 + (CH_3)_3CMgBr \rightarrow (CH_3)_3CH + C_2H_5NHMgBr$.The product formed is isobutane $((CH_3)_3CH)$.

What is the product obtained when the product of alkaline hydrolysis of $C_2H_5 - N = C = O$ is reacted with $t$-butyl magnesium bromide?

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