Which of the following compounds are colourle | vedclass

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(A) To determine if a compound is colourless,we check for the presence of unpaired electrons ($d-d$ transition). If the number of unpaired electrons $

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$TiF_6^{2-}$ and $Cu_2Cl_2$

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(A) To determine if a compound is colourless,we check for the presence of unpaired electrons ($d-d$ transition). If the number of unpaired electrons $(n)$ is $0$,the compound is colourless.      $TiF_6^{2-}$    $Cu_2Cl_2$        $Ti^{4+}: 3d^0$    $Cu^{+}: 3d^{10}$        $n = 0$    $n = 0$  For $CoF_6^{3-}$,$Co^{3+}$ is $3d^6$ ($n=4$,paramagnetic,coloured).For $NiCl_4^{2-}$,$Ni^{2+}$ is $3d^8$ ($n=2$,paramagnetic,coloured).Thus,$TiF_6^{2-}$ and $Cu_2Cl_2$ are colourless.

Which of the following compounds are colourless? ($TiF_6^{2-}, CoF_6^{3-}, Cu_2Cl_2$ and $NiCl_4^{2-}$) (Atomic numbers: $Ti = 22, Co = 27, Cu = 29, Ni = 28$)

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