What happens when potassium chromate reacts with dilute nitric acid?
- A$Cr^{3+}$ and $Cr_2O_7^{2-}$ are formed.
- B$Cr_2O_7^{2-}$ and $H_2O$ are formed.
- C$Cr_2O_7^{2-}$ and $Cr^{3+}$ oxidation state.
- D$Cr_2O_7^{2-}$ is the oxidized form of $Cr$ in $+7$ state.
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Copper sulphate is not used:
Easy
View Solution$I$. $4FeCr_2O_4 + 16NaOH + 7O_2 \rightarrow 8Na_2CrO_4 + 2Fe_2O_3 + 8H_2O$ (where $A = Na_2CrO_4$)
$II$. $2Na_2CrO_4 + H_2SO_4 \rightarrow Na_2Cr_2O_7 + Na_2SO_4 + H_2O$ (where $B = H_2SO_4$)
Compounds $(A)$ and $(B)$ are :
$II$. $2Na_2CrO_4 + H_2SO_4 \rightarrow Na_2Cr_2O_7 + Na_2SO_4 + H_2O$ (where $B = H_2SO_4$)
Compounds $(A)$ and $(B)$ are :
Medium
View SolutionCompounds of $d-$block elements can stabilize in higher oxidation states only with $F$ and $O$. Which statement is incorrect?
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View SolutionDescribe the preparation of potassium dichromate from iron chromite ore. What is the effect of increasing $pH$ on a solution of potassium dichromate?
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View SolutionIdentify the incorrect statement.
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