What is the electronic configuration of $Ce$ $(Z = 58)$?

  • A
    $[Xe] \, 4f^2 \, 5d^0 \, 6s^2$
  • B
    $[Xe] \, 4f^1 \, 5d^1 \, 6s^2$
  • C
    $[Xe] \, 4f^2 \, 5d^1 \, 6s^1$
  • D
    $[Xe] \, 4f^0 \, 5d^2 \, 6s^2$

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Consider the following statements:
$I$. $La(OH)_3$ is the least basic among hydroxides of lanthanides.
$II$. $Zr^{4+}$ and $Hf^{4+}$ possess almost the same ionic radii.
$III$. $Ce^{4+}$ can act as an oxidizing agent.
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