(A) The electronic configuration of $Ni$ is $[Ar] 3d^8 4s^2$. For $Ni^{2+}$,the configuration is $[Ar] 3d^8$. In the $3d$ subshell,there are $2$ unpai

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(A) The electronic configuration of $Ni$ is $[Ar] 3d^8 4s^2$. For $Ni^{2+}$,the configuration is $[Ar] 3d^8$. In the $3d$ subshell,there are $2$ unpaired electrons $(n = 2)$. The spin-only magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ B.M$. Substituting $n = 2$: $\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.84 \ B.M$.