What is produced when benzene is alkylated wi | vedclass

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(B) The reaction proceeds via the formation of a carbocation intermediate. $n$-propyl chloride reacts with $AlCl_3$ to form a primary carbocation,whic

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Isopropylbenzene

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(B) The reaction proceeds via the formation of a carbocation intermediate. $n$-propyl chloride reacts with $AlCl_3$ to form a primary carbocation,which undergoes a $1,2$-hydride shift to form a more stable secondary isopropyl carbocation. $CH_3-CH_2-CH_2-Cl + AlCl_3 ightarrow CH_3-CH_2-CH_2^+ + AlCl_4^-$$CH_3-CH_2-CH_2^+ \xrightarrow{	ext{1,2-hydride shift}} CH_3-CH^+-CH_3$This secondary carbocation then attacks the benzene ring to form isopropylbenzene (cumene) as the major product.

What is produced when benzene is alkylated with $n$-propyl chloride in the presence of anhydrous $AlCl_3$?

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Benzene $ + (CH_3)_3C-CH_2Cl \xrightarrow{AlCl_3} \text{Major product}$

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