Markovnikov's rule guides the addition of HBr | vedclass

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Question

(D) Markovnikov's rule is applicable to unsymmetrical alkenes. In an unsymmetrical alkene,the negative part of the addendum $(Br^-)$ attaches to the c

Vedclass · Accepted Answer

$CH_3 - CH = CH_2$

Vedclass · Answer

(D) Markovnikov's rule is applicable to unsymmetrical alkenes. In an unsymmetrical alkene,the negative part of the addendum $(Br^-)$ attaches to the carbon atom of the double bond that has the fewer number of hydrogen atoms. Among the given options,$CH_3 - CH = CH_2$ (propene) is an unsymmetrical alkene,whereas $CH_2 = CH_2$ and $CH_3 - CH = CH - CH_3$ are symmetrical alkenes. Therefore,the correct answer is $CH_3 - CH = CH_2$.

Markovnikov's rule guides the addition of $HBr$ to which of the following compounds?

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