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(A) To find the percentage of hydrogen by mass,we use the formula: $	ext{Percentage of H} = \frac{	ext{Mass of H}}{	ext{Molar mass of compound}}

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$CH_4$

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(A) To find the percentage of hydrogen by mass,we use the formula: $	ext{Percentage of H} = \frac{	ext{Mass of H}}{	ext{Molar mass of compound}} 	imes 100$. $1$. For $CH_4$: Molar mass = $12 + 4 = 16 \ g/mol$. Mass of $H$ = $4 \ g$. Percentage = $(4/16) 	imes 100 = 25\%$. $2$. For $C_2H_4$: Molar mass = $24 + 4 = 28 \ g/mol$. Mass of $H$ = $4 \ g$. Percentage = $(4/28) 	imes 100 \approx 14.28\%$. $3$. For $C_6H_6$: Molar mass = $72 + 6 = 78 \ g/mol$. Mass of $H$ = $6 \ g$. Percentage = $(6/78) 	imes 100 \approx 7.69\%$. $4$. For $C_2H_2$: Molar mass = $24 + 2 = 26 \ g/mol$. Mass of $H$ = $2 \ g$. Percentage = $(2/26) 	imes 100 \approx 7.69\%$. Comparing these,$CH_4$ has the highest percentage of hydrogen.

Which compound has the highest percentage of hydrogen by mass?

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