What is the major product formed when $cis-2-butene$ reacts with $Br_2$ in $CCl_4$?

  • A
    $1-bromo-2-butene$
  • B
    $2,3-dibromobutane$
  • C
    $meso-2,3-dibromobutane$
  • D
    $(\pm)-2,3-dibromobutane$

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Reaction $(1): CH_3-CH=CH-CH_3$ $\xrightarrow{\text{Cold } KMnO_4} (A)$ $\xrightarrow{NaIO_4} (B)$ ($2$ moles)
Reaction $(2): CH_3-CH=CH-CH_3 \xrightarrow{KMnO_4/NaIO_4} (C)$ ($2$ moles)
Product $(B)$ and $(C)$ respectively are:

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Among the alkenes, which one produces tertiary butyl alcohol on acid hydration?

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