In the reaction CH_3CH=CH_2 + H_2O + [O] xrig | vedclass

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(B) The reaction involves the oxidative cleavage of propene$-1,2-$diol using $KMnO_4$ in an acidic medium.The initial step is the hydroxylation of pro

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$CH_3COOH$

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(B) The reaction involves the oxidative cleavage of propene$-1,2-$diol using $KMnO_4$ in an acidic medium.The initial step is the hydroxylation of propene to form propane$-1,2-$diol $(CH_3-CH(OH)-CH_2OH)$.Further oxidation of propane$-1,2-$diol with $KMnO_4$ leads to the cleavage of the $C-C$ bond between the two hydroxyl-bearing carbons.The cleavage of $CH_3-CH(OH)-CH_2OH$ results in the formation of acetic acid $(CH_3COOH)$ and formic acid $(HCOOH)$.Therefore,$X$ is $CH_3COOH$.

In the reaction $CH_3CH=CH_2 + H_2O + [O]$ $\xrightarrow{KMnO_4/Acid} CH_3-CH(OH)-CH_2(OH)$ $\xrightarrow{[O]} X + HCOOH$,what is $X$?

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