Consider the following reaction: CH_2 = CH_2 | vedclass

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(B) The reaction of ethene with dilute alkaline $KMnO_4$ (Baeyer's reagent) is a syn-hydroxylation reaction.In this mechanism,the two oxygen atoms add

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Both are obtained from $H_2O$.

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(B) The reaction of ethene with dilute alkaline $KMnO_4$ (Baeyer's reagent) is a syn-hydroxylation reaction.In this mechanism,the two oxygen atoms added to the double bond are derived from the permanganate ion $(MnO_4^-)$.Therefore,the statement that both oxygen atoms are obtained from $KMnO_4$ is correct.Statements $B$,$C$,and $D$ are incorrect as they suggest the oxygen atoms come from $H_2O$ or $NaOH$.

Consider the following reaction: $CH_2 = CH_2 \xrightarrow[H_2O, NaOH]{dilute \ KMnO_4} HOCH_2 - CH_2OH$. Which statement is incorrect regarding the two oxygen atoms obtained in the product?

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