Determine the IUPAC name of the given compoun | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given structure is $CH_3-CH=CH-CH=CH-CH_3$. Numbering from either end gives the double bonds at positions $2$ and $4$. For the double bond at

Vedclass · Accepted Answer

$(2E, 4E)-hexa-2,4-diene$

Vedclass · Answer

(D) The given structure is $CH_3-CH=CH-CH=CH-CH_3$. Numbering from either end gives the double bonds at positions $2$ and $4$. For the double bond at $C2$,the higher priority groups (the methyl group and the rest of the chain) are on opposite sides,which corresponds to the $E$ configuration. For the double bond at $C4$,the higher priority groups are also on opposite sides,which corresponds to the $E$ configuration. Therefore,the $IUPAC$ name is $(2E, 4E)-hexa-2,4-diene$.

Determine the $IUPAC$ name of the given compound.

Similar Questions

The correct $IUPAC$ name for the compound shown below is:

What is the number of carbon atoms in the longest chain of the given compound?
$CH_3 - CH_2 - CH_2 - C(=O) - CH(CHO) - CH_2 - CH_3$ (Note: The structure provided in the input was interpreted as a heptane derivative with a substituent).

The $IUPAC$ name of the given compound is:

Choose the correct $IUPAC$ name of the compound $CH_3-CH(CH_3)-CH(CH_3)-C\equiv C-CH_3$.

Names of some compounds are given. Which one is not in $IUPAC$ system?

Vedclass Test Series

Exam Paper Generator

Online Exam Module