Which of the following is the correct decreas | vedclass

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(B) The stability of carbanions is determined by the inductive effect ($+I$ effect) and resonance.$(1) (CH_3)_3C^-$ is a tertiary carbanion,$(2) (CH_3

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$4 > 3 > 2 > 1$

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(B) The stability of carbanions is determined by the inductive effect ($+I$ effect) and resonance.$(1) (CH_3)_3C^-$ is a tertiary carbanion,$(2) (CH_3)_2CH^-$ is a secondary carbanion,and $(3) CH_3CH_2^-$ is a primary carbanion. The $+I$ effect of alkyl groups destabilizes the carbanion,so stability follows the order: $1^\circ > 2^\circ > 3^\circ$.$(4) C_6H_5CH_2^-$ is a benzyl carbanion,which is stabilized by resonance with the phenyl ring,making it more stable than the alkyl carbanions.Thus,the decreasing order of stability is: $C_6H_5CH_2^- (4) > CH_3CH_2^- (3) > (CH_3)_2CH^- (2) > (CH_3)_3C^- (1)$.

Column-$I$	Column-$II$
$A$. $CH_3-O^{+}=CH-CH_3$	$1$. Stable due to resonance
$B$. $F_3C^{+}$	$2$. Destabilised due to inductive effect
$C$. $(CH_3)_3C^{-}$	$3$. Stabilised by hyperconjugation
$D$. $CH_3-CH^{+}-CH_3$	$4$. $A$ secondary carbocation

Which of the following is the correct decreasing order of stability of carbanions?
$(1) (CH_3)_3C^-$
$(2) (CH_3)_2CH^-$
$(3) CH_3CH_2^-$
$(4) C_6H_5CH_2^-$

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Which of the following is the correct decreasing order of stability of carbanions?$(1) (CH_3)_3C^-$$(2) (CH_3)_2CH^-$$(3) CH_3CH_2^-$$(4) C_6H_5CH_2^-$