The reaction of methyltrichloroacetate (Cl_{3 | vedclass

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Question

(B) The reaction of methyltrichloroacetate $(Cl_{3}CCO_{2}Me)$ with sodium methoxide $(NaOMe)$ involves the nucleophilic attack of the methoxide ion $

Vedclass · Accepted Answer

carbene

Vedclass · Answer

(B) The reaction of methyltrichloroacetate $(Cl_{3}CCO_{2}Me)$ with sodium methoxide $(NaOMe)$ involves the nucleophilic attack of the methoxide ion $(^-OMe)$ on the carbonyl carbon of the ester.This leads to the formation of a tetrahedral intermediate, which then collapses to eliminate the trichloromethyl carbanion $(^-CCl_{3})$.The trichloromethyl carbanion $(^-CCl_{3})$ is unstable and subsequently loses a chloride ion $(Cl^-)$ to generate dichlorocarbene $(:CCl_{2})$.Therefore, the final reactive intermediate generated in this process is a carbene.

The reaction of methyltrichloroacetate $(Cl_{3}CCO_{2}Me)$ with sodium methoxide $(NaOMe)$ generates

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