Which of the following is the most stable car | vedclass

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(D) The stability of carbocations is determined by resonance and inductive effects.Option $A$ $(CH_3 - \mathop C\limits^\oplus H_2)$ is a primary carb

Vedclass · Accepted Answer

$\mathop C\limits^\oplus H_2 - OCH_3$

Vedclass · Answer

(D) The stability of carbocations is determined by resonance and inductive effects.Option $A$ $(CH_3 - \mathop C\limits^\oplus H_2)$ is a primary carbocation with only inductive stabilization.Option $C$ $(\mathop C\limits^\oplus H_2CH_2Cl)$ is destabilized by the electron-withdrawing $-I$ effect of the chlorine atom.Option $B$ $(Ph - \mathop C\limits^\oplus H_2)$ is resonance stabilized by the phenyl ring.Option $D$ $(\mathop C\limits^\oplus H_2 - OCH_3)$ is resonance stabilized by the lone pair on the oxygen atom.In option $D$,the oxygen atom donates its lone pair to form a double bond,resulting in a structure where all atoms (including the carbon) have a complete octet $(CH_2 = \mathop O\limits^\oplus - CH_3)$.Since the octet is complete for all atoms in the resonance structure of $D$,it is significantly more stable than the resonance-stabilized benzyl carbocation $(B)$,where the positive charge is delocalized into the ring but the octet of the benzylic carbon is not completed in the same way.

Which of the following is the most stable carbocation?

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