Write the IUPAC name of the given compound. | vedclass

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(D) The structure is $C_6H_5-CH=CH-COOH$. The principal functional group is the carboxylic acid $(-COOH)$,which gets the $C-1$ position. The carbon ch

Vedclass · Accepted Answer

$3$-Phenylprop-$2$-enoic acid

Vedclass · Answer

(D) The structure is $C_6H_5-CH=CH-COOH$. The principal functional group is the carboxylic acid $(-COOH)$,which gets the $C-1$ position. The carbon chain consists of $3$ carbons,so the parent alkane is propane. The double bond starts at $C-2$,so it is a prop-$2$-enoic acid derivative. $A$ phenyl group $(-C_6H_5)$ is attached at the $C-3$ position. Therefore,the $IUPAC$ name is $3$-phenylprop-$2$-enoic acid.

Write the $IUPAC$ name of the given compound.

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