Which of the following does not contain an sp | vedclass

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(C) To determine the hybridization of carbon atoms,we look at the number of sigma bonds and lone pairs attached to the carbon atom.$1$. Acetamide $(CH

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Acetonitrile

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(C) To determine the hybridization of carbon atoms,we look at the number of sigma bonds and lone pairs attached to the carbon atom.$1$. Acetamide $(CH_3CONH_2)$: The carbonyl carbon $(C=O)$ is $sp^2$ hybridized.$2$. Acetic acid $(CH_3COOH)$: The carbonyl carbon $(C=O)$ is $sp^2$ hybridized.$3$. Acetonitrile $(CH_3C \equiv N)$: The methyl carbon is $sp^3$ hybridized,and the nitrile carbon $(C \equiv N)$ is $sp$ hybridized. Thus,it contains no $sp^2$ hybridized carbon.$4$. Acetone $(CH_3COCH_3)$: The carbonyl carbon $(C=O)$ is $sp^2$ hybridized.Therefore,the correct option is $C$.

Which of the following does not contain an $sp^2$ hybridized carbon?

Similar Questions

Which of the following compounds do not have $sp^3$ carbon atom$(s)$?
$I$. Acetone
$II$. Acetic acid
$III$. Buta-$1,3$-diene
$IV$. Propyne
$V$. Naphthalene

Select the response that correctly identifies the number of carbon atoms of each type of hybridization in the compound given below:
$H_2C=C=CH-CHO$
(Order: $sp^3 - sp^2 - sp$)

The bond between carbon atom $(1)$ and carbon atom $(2)$ in compound $N \equiv C - CH = CH_2$ involves the hybridised carbon as

What is the hybridization of carbon atoms at positions $1$,$3$,and $5$ in the compound $CH_3-CH=CH-CH_2-C \equiv CH$?

In the molecule $HC \equiv C - CH_2 - CH = CH - CH_3$,what is the type of hybridization for the $C_2 - C_3$ bond?

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