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(B) Nucleophilic substitution reactions are favored by the presence of electron-withdrawing groups $(EWG)$ on the aromatic ring,as they decrease the e

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$I < II < III$

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(B) Nucleophilic substitution reactions are favored by the presence of electron-withdrawing groups $(EWG)$ on the aromatic ring,as they decrease the electron density and stabilize the intermediate carbanion (Meisenheimer complex).$(I)$ $C_6H_5-CH_3$: The $-CH_3$ group is an electron-donating group $(EDG)$ due to the $+I$ effect and hyperconjugation,which decreases reactivity towards nucleophiles.$(II)$ $C_6H_6$: Benzene has no substituent.$(III)$ $C_6H_5-COOH$: The $-COOH$ group is a strong electron-withdrawing group $(EWG)$ due to the $-I$ and $-M$ effects,which significantly increases reactivity towards nucleophiles.Therefore,the reactivity order is: $I < II < III$.

What is the increasing order of nucleophilic substitution reaction for the following compounds?
$(I)$ $C_6H_5-CH_3$
$(II)$ $C_6H_6$
$(III)$ $C_6H_5-COOH$

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What is the increasing order of nucleophilic substitution reaction for the following compounds? $(I)$ $C_6H_5-CH_3$ $(II)$ $C_6H_6$ $(III)$ $C_6H_5-COOH$