Nickel $(Z = 28)$ forms a paramagnetic complex $[NiX_4]^{2-}$ with a uninegative monodentate ligand $X^-$. The number of unpaired electrons in nickel and the geometry of this complex ion are,respectively:
- AOne,Square planar
- BTwo,Square planar
- COne,Tetrahedral
- DTwo,Tetrahedral
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Which of the following complexes involves $4p$ orbitals for hybridization?
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Match each set of hybrid orbitals from $LIST-I$ with complex(es) given in $LIST-II$. The correct option is
$LIST-I$ $LIST-II$ $P. dsp^2$ $1. [FeF_6]^{4-}$ $Q. sp^3$ $2. [Ti(H_2O)_3Cl_3]$ $R. sp^3d^2$ $3. [Cr(NH_3)_6]^{3+}$ $S. d^2sp^3$ $4. [FeCl_4]^{2-}$ $5. Ni(CO)_4$ $6. [Ni(CN)_4]^{2-}$
| $LIST-I$ | $LIST-II$ |
| $P. dsp^2$ | $1. [FeF_6]^{4-}$ |
| $Q. sp^3$ | $2. [Ti(H_2O)_3Cl_3]$ |
| $R. sp^3d^2$ | $3. [Cr(NH_3)_6]^{3+}$ |
| $S. d^2sp^3$ | $4. [FeCl_4]^{2-}$ |
| $5. Ni(CO)_4$ | |
| $6. [Ni(CN)_4]^{2-}$ |
MediumIIT 2018
View Solution$[Cr(H_2O)_6]Cl_3$ $(At. \text{ } no. \text{ } of \text{ } Cr = 24)$ has a magnetic moment of $3.83 \text{ } B.M.$ The correct distribution of $3d$ electrons in the chromium of the complex is
DifficultAIPMT 2006
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