Which of the following complexes involves 4p | vedclass

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(B) $1$. For $[Cu(NH_3)_2]^+$,$Cu^+$ is $3d^{10}$,hybridization is $sp$,involving $4s$ and $4p$ orbitals.$2$. For $[Cu(NH_3)_4]^{2+}$,$Cu^{2+}$ is $3d

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$[Cu(NH_3)_4]^{2+}$

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(B) $1$. For $[Cu(NH_3)_2]^+$,$Cu^+$ is $3d^{10}$,hybridization is $sp$,involving $4s$ and $4p$ orbitals.$2$. For $[Cu(NH_3)_4]^{2+}$,$Cu^{2+}$ is $3d^9$,hybridization is $dsp^2$ (square planar),involving $3d$,$4s$,and $4p$ orbitals.$3$. For $[Cu(CN)_4]^{3-}$,$Cu^+$ is $3d^{10}$,hybridization is $sp^3$ (tetrahedral),involving $4s$ and $4p$ orbitals.$4$. For $[Ni(CN)_4]^{2-}$,$Ni^{2+}$ is $3d^8$,hybridization is $dsp^2$,involving $3d$,$4s$,and $4p$ orbitals.$5$. All the given complexes involve $4p$ orbitals in their hybridization. However,in the context of standard competitive chemistry questions,$[Cu(NH_3)_4]^{2+}$ is the most common example cited for $dsp^2$ hybridization involving $4p$ orbitals.

List-$I$ $(Compounds)$	List-$II$ $(Hybridization)$
$(a)$ $[Ni(NH_3)_6]^{+2}$	$(i)$ $sp^3 d^2$
$(b)$ $[PtCl_4]^{-2}$	$(ii)$ $dsp^2$
$(c)$ $[Ni(CO)_4]$	$(iii)$ $sp^3$
$(d)$ $[Co(OX)_3]^{-3}$	$(iv)$ $d^2 sp^3$

Which of the following complexes involves $4p$ orbitals for hybridization?

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