For the coordination compound [Co(NH_3)_5CO_3 | vedclass

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(A) $1$. The coordination number of $Co$ is determined by the ligands: $5$ from $NH_3$ (monodentate) and $1$ from $CO_3^{2-}$ (bidentate),so $5 + 2 =

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$6, 3, 6, 0$

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(A) $1$. The coordination number of $Co$ is determined by the ligands: $5$ from $NH_3$ (monodentate) and $1$ from $CO_3^{2-}$ (bidentate),so $5 + 2 = 7$ is incorrect; wait,$CO_3^{2-}$ acts as a bidentate ligand,so $5 + 2 = 7$. However,in this specific complex $[Co(NH_3)_5CO_3]^+$,the $CO_3^{2-}$ is often treated as monodentate in some contexts,but standard $IUPAC$ considers it bidentate. Let's re-evaluate: $5(NH_3) + 1(CO_3) = 6$ coordination sites. $2$. Oxidation state: $x + 5(0) + 1(-2) = +1$ (since $ClO_4$ is $-1$),so $x - 2 = +1$,$x = +3$. $3$. Electronic configuration of $Co$ $(Z=27)$ is $[Ar] 3d^7 4s^2$. For $Co^{3+}$,it is $[Ar] 3d^6$. $4$. Number of electrons in $d$-orbitals is $6$. $5$. Since $NH_3$ is a strong field ligand,it causes pairing. For $d^6$ in an octahedral field,all electrons are paired,so unpaired electrons = $0$.

$LIST-I$	$LIST-II$
$P. dsp^2$	$1. [FeF_6]^{4-}$
$Q. sp^3$	$2. [Ti(H_2O)_3Cl_3]$
$R. sp^3d^2$	$3. [Cr(NH_3)_6]^{3+}$
$S. d^2sp^3$	$4. [FeCl_4]^{2-}$
	$5. Ni(CO)_4$
	$6. [Ni(CN)_4]^{2-}$

For the coordination compound $[Co(NH_3)_5CO_3]ClO_4$,what are the coordination number,oxidation state,number of electrons in the $d$-orbitals,and the number of unpaired electrons for the central metal $Co$?

Similar Questions

Consider the reaction $K_2[Ni(CN)_4] + 4K + 4NH_3 \to A$ (complex $A$).
Complex $A$ gives five ions in aqueous solution. Choose the $CORRECT$ statements.

The number of species from the following that are involved in $sp^3 d^2$ hybridization is $[Co(NH_3)_6]^{3+}, SF_6, [CrF_6]^{3-}, [CoF_6]^{3-}, [Mn(CN)_6]^{3-}$ and $[MnCl_6]^{3-}$.

Match each set of hybrid orbitals from $LIST-I$ with complex(es) given in $LIST-II$. The correct option is

$LIST-I$ $LIST-II$

$P. dsp^2$ $1. [FeF_6]^{4-}$

$Q. sp^3$ $2. [Ti(H_2O)_3Cl_3]$

$R. sp^3d^2$ $3. [Cr(NH_3)_6]^{3+}$

$S. d^2sp^3$ $4. [FeCl_4]^{2-}$

$5. Ni(CO)_4$

$6. [Ni(CN)_4]^{2-}$

What is the magnetic moment (spin only) and hybridisation of the brown ring complex $[Fe(H_2O)_5NO]SO_4$?

The geometries of $Ni(CO)_4$ and $Ni(PPh_3)_2Cl_2$ are:

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