The electronic configurations of Cr^{2+}, Mn^ | vedclass

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(C) The magnetic moment is directly proportional to the number of unpaired electrons $(n)$.For $[Cr(H_2O)_6]^{2+}$,the configuration is $3d^4$,so $n =

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$[Ni(H_2O)_6]^{2+}$

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(C) The magnetic moment is directly proportional to the number of unpaired electrons $(n)$.For $[Cr(H_2O)_6]^{2+}$,the configuration is $3d^4$,so $n = 4$.For $[Mn(H_2O)_6]^{2+}$,the configuration is $3d^5$,so $n = 5$.For $[Fe(H_2O)_6]^{2+}$,the configuration is $3d^6$,so $n = 4$.For $[Ni(H_2O)_6]^{2+}$,the configuration is $3d^8$,so $n = 2$.Since $[Ni(H_2O)_6]^{2+}$ has the minimum number of unpaired electrons $(n = 2)$,it exhibits the minimum paramagnetic behavior.

Compound	Total stereoisomers
$A$. $[Co(en)_2Cl_2]^+$	$P$. $2$
$B$. $[Co(en)_3]Cl_3$	$Q$. $3$
$C$. $[Pt(NH_3)_2Cl_2]$	$R$. $4$
$D$. $[Pt(NH_3)_3Cl_3]^+$	$S$. $5$

The electronic configurations of $Cr^{2+}, Mn^{2+}, Fe^{2+}$ and $Ni^{2+}$ ions are $3d^4, 3d^5, 3d^6$ and $3d^8$ respectively. Which of the following aqua complexes exhibits the minimum paramagnetic behavior?

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What will be the value of $x$ in $Fe^{x+}$,if the magnetic moment,$\mu=\sqrt{24} \ BM$?

Compound Total stereoisomers
$A$. $[Co(en)_2Cl_2]^+$ $P$. $2$
$B$. $[Co(en)_3]Cl_3$ $Q$. $3$
$C$. $[Pt(NH_3)_2Cl_2]$ $R$. $4$
$D$. $[Pt(NH_3)_3Cl_3]^+$ $S$. $5$

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The types of isomerism shown by $[Cr(NH_3)_5NO_2]Cl_2$ are:

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