Which of the following is expected to be a pa | vedclass

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(A) To determine paramagnetism,we check for unpaired electrons in the central metal ion: $1$. In $[Ni(H_2O)_6]^{2+}$,$Ni$ is in the $+2$ oxidation sta

Vedclass · Accepted Answer

$[Ni(H_2O)_6]^{2+}$

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(A) To determine paramagnetism,we check for unpaired electrons in the central metal ion: $1$. In $[Ni(H_2O)_6]^{2+}$,$Ni$ is in the $+2$ oxidation state $(3d^8)$. $H_2O$ is a weak field ligand,so the configuration is $t_{2g}^6 e_g^2$,which has $2$ unpaired electrons. Thus,it is paramagnetic. $2$. In $[Ni(CO)_4]$,$Ni$ is in the $0$ oxidation state $(3d^8 4s^2)$. $CO$ is a strong field ligand,causing pairing to form $3d^{10}$,which is diamagnetic. $3$. In $[Zn(NH_3)_4]^{2+}$,$Zn$ is in the $+2$ oxidation state $(3d^{10})$,which is diamagnetic. $4$. In $[Co(NH_3)_6]^{3+}$,$Co$ is in the $+3$ oxidation state $(3d^6)$. $NH_3$ is a strong field ligand,causing pairing to form $t_{2g}^6 e_g^0$,which is diamagnetic.

List-$I$ (Coordination compounds)	List-$II$ (Number of unpaired electrons)
$A$. $[Cr(CN)_6]^{3-}$	$I$. $0$
$B$. $[Fe(H_2O)_6]^{2+}$	$II$. $3$
$C$. $[Co(NH_3)_6]^{3+}$	$III$. $2$
$D$. $[Ni(NH_3)_6]^{2+}$	$IV$. $4$

Which of the following is expected to be a paramagnetic complex?

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