An aqueous solution of the complex [Cu(NH_3)_ | vedclass

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(C) The complex $[Cu(NH_3)_4]SO_4$ dissociates in water as $[Cu(NH_3)_4]SO_4 \rightarrow [Cu(NH_3)_4]^{2+} + SO_4^{2-}$.Since the $SO_4^{2-}$ ion is p

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Test for $SO_4^{2-}$ ions.

Vedclass · Answer

(C) The complex $[Cu(NH_3)_4]SO_4$ dissociates in water as $[Cu(NH_3)_4]SO_4 \rightarrow [Cu(NH_3)_4]^{2+} + SO_4^{2-}$.Since the $SO_4^{2-}$ ion is present in the ionization sphere (outside the coordination entity),it is free to react and will give a positive test for sulfate ions (e.g.,with $BaCl_2$ solution).The $Cu^{2+}$ and $NH_3$ are part of the coordination sphere $[Cu(NH_3)_4]^{2+}$ and do not dissociate,so they do not give their characteristic tests.

An aqueous solution of the complex $[Cu(NH_3)_4]SO_4$ gives the test for:

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