The theoretical value of the magnetic moment | vedclass

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(B) The complex formed by $Fe^{3+}$ and $CN^{-}$ is $[Fe(CN)_6]^{3-}$.In this complex,the oxidation state of $Fe$ is $+3$,which has an electronic conf

Vedclass · Accepted Answer

$1.73$

Vedclass · Answer

(B) The complex formed by $Fe^{3+}$ and $CN^{-}$ is $[Fe(CN)_6]^{3-}$.In this complex,the oxidation state of $Fe$ is $+3$,which has an electronic configuration of $[Ar] 3d^5$.$CN^{-}$ is a strong field ligand,which causes pairing of electrons in the $3d$ orbitals.For $d^5$ configuration with strong field ligand,the electrons are arranged as $t_{2g}^5 e_g^0$,resulting in $1$ unpaired electron $(n = 1)$.The magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ B.M.$Substituting $n = 1$,we get $\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \ B.M.$

The theoretical value of the magnetic moment of the complex formed by the reaction of $Fe^{3+}$ ion with $CN^{-}$ ligand is .......... $B.M.$

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