Which of the following is an outer orbital co | vedclass

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Question

(D) An outer orbital complex is formed when the outer $d$-orbitals $(4d)$ are used in hybridization,typically involving $sp^3d^2$ hybridization.$1$. $

Vedclass · Accepted Answer

$[Ni(NH_3)_6]^{2+}$

Vedclass · Answer

(D) An outer orbital complex is formed when the outer $d$-orbitals $(4d)$ are used in hybridization,typically involving $sp^3d^2$ hybridization.$1$. $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand,causing pairing. It forms $d^2sp^3$ (inner orbital).$2$. $[Mn(CN)_6]^{4-}$: $Mn^{2+}$ is $3d^5$. $CN^-$ is a strong field ligand,causing pairing. It forms $d^2sp^3$ (inner orbital).$3$. $[Fe(CN)_6]^{4-}$: $Fe^{2+}$ is $3d^6$. $CN^-$ is a strong field ligand,causing pairing. It forms $d^2sp^3$ (inner orbital).$4$. $[Ni(NH_3)_6]^{2+}$: $Ni^{2+}$ is $3d^8$. $NH_3$ is a moderate field ligand. It forms $sp^3d^2$ hybridization using $4d$ orbitals,making it an outer orbital complex.

Column-$I$ Complex	Column-$II$ Structure / Geometry / Property
$A$. $[Ni(CN)_4]^{2-}$	$I$. Tetrahedral / Paramagnetic
$B$. $[Ni(CO)_4]$	$II$. Tetrahedral / Diamagnetic
$C$. $[NiCl_4]^{2-}$	$III$. Square planar / Diamagnetic

Which of the following is an outer orbital complex? (Atomic numbers: $Mn = 25, Fe = 26, Co = 27, Ni = 28$)

Similar Questions

Which of the following complexes exhibits $dsp^2$ hybridization?

Which statement is incorrect?

Match the following:

Column-$I$ Complex Column-$II$ Structure / Geometry / Property

$A$. $[Ni(CN)_4]^{2-}$ $I$. Tetrahedral / Paramagnetic

$B$. $[Ni(CO)_4]$ $II$. Tetrahedral / Diamagnetic

$C$. $[NiCl_4]^{2-}$ $III$. Square planar / Diamagnetic

The correct match is:

The hexachloridocobaltate $(III)$ ion is a high-spin complex. What is the possible hybridisation state of the cobalt ion in this complex?

In which of the following configurations will there be the possibility of both paramagnetism and diamagnetism,depending on the nature of the ligands?

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