What is the equation of the line passing through $(1, 2, 3)$ and perpendicular to the plane $3x + 4y - 5z = 6$?

  • A
    $\frac{x - 1}{3} = \frac{2 - y}{4} = \frac{3 - z}{5}$
  • B
    $\frac{x - 1}{3} = \frac{y - 2}{4} = \frac{3 - z}{5}$
  • C
    $\frac{x - 3}{1} = \frac{y - 4}{2} = \frac{z + 5}{3}$
  • D
    $\frac{1 - x}{3} = \frac{y - 2}{4} = \frac{z - 3}{-5}$

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