Find the axis of the parabola $9y^2 - 16x - 12y - 57 = 0$.

Let $O$ be the vertex and $Q$ be any point on the parabola $x^2=8y$. If the point $P$ divides the line segment $OQ$ internally in the ratio $1:3$, then the locus of $P$ is

If the parabola $y^2 = 4ax$ passes through the point $(1, -2)$,then the tangent at this point is

Find the equation of the parabola that satisfies the following conditions: Vertex $(0, 0)$,passing through $(5, 2)$,and symmetric with respect to the $y$-axis.

The equation of the chord of contact of the tangents drawn from the point $(2, 3)$ to the parabola $y^2 + x = 0$ is:

From a point $(C, 0)$,three normals are drawn to the parabola $y^2=x$. Then,