What is the position of the point (8, -9) wit | vedclass

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(A) Let the lines be $L_1: 2x + 3y - 4 = 0$ and $L_2: 6x + 9y + 8 = 0$. First,observe that $L_2$ can be written as $3(2x + 3y) + 8 = 0$. Substitute th

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The point lies outside the lines.

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(A) Let the lines be $L_1: 2x + 3y - 4 = 0$ and $L_2: 6x + 9y + 8 = 0$. First,observe that $L_2$ can be written as $3(2x + 3y) + 8 = 0$. Substitute the point $(8, -9)$ into the expressions: For $L_1(8, -9) = 2(8) + 3(-9) - 4 = 16 - 27 - 4 = -15$. For $L_2(8, -9) = 6(8) + 9(-9) + 8 = 48 - 81 + 8 = -25$. Since both $L_1(8, -9)$ and $L_2(8, -9)$ have the same sign (both are negative),the point $(8, -9)$ lies on the same side of both lines. Therefore,the point lies outside the region between the two parallel lines.

What is the position of the point $(8, -9)$ with respect to the lines $2x + 3y - 4 = 0$ and $6x + 9y + 8 = 0$?

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