Find the equation of the line equidistant fro | vedclass

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(D) The given lines $x = 3$ and $x = 8$ are parallel to the $Y$-axis.Any line equidistant from these two lines must also be parallel to the $Y$-axis a

Vedclass · Accepted Answer

$2x - 11 = 0$

Vedclass · Answer

(D) The given lines $x = 3$ and $x = 8$ are parallel to the $Y$-axis.Any line equidistant from these two lines must also be parallel to the $Y$-axis and will be of the form $x = k$.Since the line $x = k$ is equidistant from $x = 3$ and $x = 8$,the distance between $x = k$ and $x = 3$ must equal the distance between $x = 8$ and $x = k$.Thus,$k - 3 = 8 - k$.$2k = 11$$k = \frac{11}{2}$Therefore,the equation of the required line is $x = \frac{11}{2}$,which can be written as $2x - 11 = 0$.

Find the equation of the line equidistant from the lines $x = 3$ and $x = 8$.

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