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(A) The standard equation of a parabola is $y^2 = 4ax$. Comparing $y^2 = 18x$ with $y^2 = 4ax$,we get $4a = 18$,which implies $a = 18/4 = 9/2$. The pa

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$2/3$

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(A) The standard equation of a parabola is $y^2 = 4ax$. Comparing $y^2 = 18x$ with $y^2 = 4ax$,we get $4a = 18$,which implies $a = 18/4 = 9/2$. The parametric coordinates of a point on the parabola $y^2 = 4ax$ are given by $(at^2, 2at)$. Given the point $(2, 6)$,we have $at^2 = 2$ and $2at = 6$. From $2at = 6$,we get $at = 3$. Substituting $a = 9/2$ into $at = 3$,we get $(9/2)t = 3$. Solving for $t$,we get $t = 3 	imes (2/9) = 6/9 = 2/3$. Thus,the value of the parameter $t$ is $2/3$.

What is the value of the parameter $t$ for the point $(2, 6)$ on the parabola $y^2 = 18x$?

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